So, you have written your rate equation and the next question asks you to
suggest a rate determining step.
The key phrase here is
suggest, when ever you see this the examiner is telling you that there are lots of possible answers, you just have to come up with one of them. There is an implication in the word "suggest" that there is some educated guess work involved.
So what do you suggest?
Let's look at an example...
Here is an overall reaction
Here is the rate equation
Question - Suggest a rate determining step.
In this relatively simple example, the rate equation tells me that the OH- isn't involved in the slow step. It is only the (CH3)3CBr. The implication is that the OH- comes in to play in some unknown later fast step, I guess theoretically it could be involved in an earlier fast step but realistcally what can OH- do on its own in a first step?
So, all we know is that the rate determining step has (CH3)3CBr as a reactant and nothing else, giving us...
(CH3)3CBr -->
What about the products?
Well you would get away with "intermediates", i.e.
(CH3)3CBr --> intermediates
but in this question you can do better than that
because if all you have is one molecule of (CH3)3Br on its own it must fall apart and logically what must fall off is the Br-. As it is a product in the full equation. This gives us
(CH3)3CBr --> (CH3)3C+ and Br- as the slow (rate determining) step
and then theoretically
(CH3)3C+ and OH- --> (CH3)3COH as the the fast step.
Will that get you the marks in the exams? Yep
Is that what really happens? Doesn't matter