Here is a long (and a little
mathsy explanation) of what an order of a reaction is.
The
maths here is pretty basic, as long as you understand POWERs (e.g. squaring) then it is LOVEly. Pretty awful
justification of the blog post title. Lets move on.
You know
from GCSE (or earlier) that as you increase concentration, rate increases.
Greater chance of collision, more succesful collision, blah, blah, blah... You
might even have learnt that concentration and rate are directly
proportional.
At A
level you learn that both of these facts are only true some of the time. In
reality, you will now learn there are three different options (in reality there
are more than that but lets not get into that now)
Option A
- Some
reactants as you increase their concentration, the rate is not changed,
these are called zero order
reactants. In other words put in as much of it as you want, it ain't going any
faster.
Option B
- Some
reactants as you increase their concentration, the rate increase
proportionally (i.e. double conc = double rate),
these are called first order reactants.
In other words, pretty much what a GCSE student would've predicted
Option C - Some reactants as you
increase their concentration, the rate changes
by that number squared (i.e. double conc = quadruple rate, triple conc = 9
times increase in rate etc.) , these are called second order
reactants. In other words more of this stuff really gets reactions going.
You need
to understand where these numbers (zero, first, second) come from. These numbers
(or orders) are needed as powers in the equations so that they works
mathematically
So, (in
case you've forgotten) the rate equation is
Rate = k
x [Conc].
If it
is zero order, that
gives us, Rate = k x [Conc]0,
and as
anything to the power zero = 1
that
gives us
Rate = k
x 1 or Rate = k
in other words, Concentration
of the reactant is not in the equation so it doesn't affect rate. (Just
like I said in Option A above)
If it is first order, that
gives us, Rate = k x [Conc]1,
and as the
power 1 doesn't change anything
that gives us
Rate = k x
[Conc]
in other
words, Concentration
of the reactant is directly proportional to rate. (Just
like I said in Option B above)
If it is second order, that
gives us, Rate = k x [Conc]2,
in other
words, If you double Concentration
of the reactant the rate goes up by that number squared. So
a doubling of a [Conc] would lead to a quadrupling of the rate as 22
= 4. (Just like I said in Option C above)
So what is the
order?
It is
the power, to which you raise the concentration in the rate
equation.
If you read
through the whole post, and understand it that last statement is almost
pointlessly obvious